-4[3x-3-7(x+1)]=4x+6

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Solution for -4[3x-3-7(x+1)]=4x+6 equation:


Simplifying
-4[3x + -3 + -7(x + 1)] = 4x + 6

Reorder the terms:
-4[3x + -3 + -7(1 + x)] = 4x + 6
-4[3x + -3 + (1 * -7 + x * -7)] = 4x + 6
-4[3x + -3 + (-7 + -7x)] = 4x + 6

Reorder the terms:
-4[-3 + -7 + 3x + -7x] = 4x + 6

Combine like terms: -3 + -7 = -10
-4[-10 + 3x + -7x] = 4x + 6

Combine like terms: 3x + -7x = -4x
-4[-10 + -4x] = 4x + 6
[-10 * -4 + -4x * -4] = 4x + 6
[40 + 16x] = 4x + 6

Reorder the terms:
40 + 16x = 6 + 4x

Solving
40 + 16x = 6 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
40 + 16x + -4x = 6 + 4x + -4x

Combine like terms: 16x + -4x = 12x
40 + 12x = 6 + 4x + -4x

Combine like terms: 4x + -4x = 0
40 + 12x = 6 + 0
40 + 12x = 6

Add '-40' to each side of the equation.
40 + -40 + 12x = 6 + -40

Combine like terms: 40 + -40 = 0
0 + 12x = 6 + -40
12x = 6 + -40

Combine like terms: 6 + -40 = -34
12x = -34

Divide each side by '12'.
x = -2.833333333

Simplifying
x = -2.833333333

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